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  5. Pharaoh's Servant (25th Anniversary Edition)
  6. Chain Destruction

Yu-Gi-Oh! · Pharaoh's Servant (25th Anniversary Edition) · #PSV-EN006 · Ultra Rare

Chain Destruction

Yu-Gi-Oh! card price for Chain Destruction: $3.74 market, from $3.49 at the cheapest listing, Unlimited printing, updated Oct 18, 2026. Full price history since Feb 8, 2024 below.

Market price · Unlimited · Oct 18, 2026
$3.74
−0.3% this week · −1.8% in 30 days
Buy on eBay →
1 day−0.3%
7 days−0.3%
30 days−1.8%
90 days−6.5%
1 year−19.7%
All time+87.0%

Sellers right now

$3.49lowest listing$95.82highest
Market price$3.74
Mid listing$3.99
Direct$17.59
30-day avg$3.79

Market price is what a near-mint copy actually sold for. The cheapest listing is what a seller asks today — on thin markets the two differ a lot.

Where to buy

One year

$3.7352-week low$4.7352-week high
In the range1%
All-time low$1.87
All-time high$14.42
First priceFeb 8, 2024
Unlimited · market price
$1.25$6.06$10.86$15.66
$3.74
Feb 2024Dec 2024Nov 2025Oct 2026
TCGplayer market price · via tcgcsvtcgrate.com

Price story

We have tracked Chain Destruction since February 2024, when it sold for $2.00. Today the market price is $3.74, up 87.0%. Across the past year it went −19.7%, with a low of $3.73 and a high of $4.73; today it sits near the bottom of that range. Its all-time high in our data is $14.42, still 286% above the current price. The cheapest listing right now is $3.49, and the 30-day average market price is $3.79.

Printings

PrintingMarketLowHigh7d
Unlimited$3.74$3.49$95.82−0.3%

The card in play

ATK0
DEF0
Card type
Normal Trap
Attribute
TRAP
Card text

You can activate this card when a monster with an ATK of 2000 points or less is summoned (including Special Summon). This monster is not destroyed, but all Monster Cards of the same name in the summoning player''s hand and Deck are destroyed. The summoning player''s Deck is then shuffled.

Other printings of Chain Destruction

11 more · $0.12 – $17.72
All printings

Also in Pharaoh's Servant (25th Anniversary Edition)

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Full set